Some Scottish students felt the National 5 Maths Exam was too difficult, particularly this tricky umbrella question. The test is not yet released, so I have re-constructed the problem as best as I could from accounts of the exam. Here is the problem: “Can an umbrella 85 cm long fit diagonally inside a locker with length 40 cm, width 40 cm, and height 70 cm?”

My blog post for this video

Source: The Scottish Sun

Thanks to Max Krass finding a mistake in the early access version:

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## 25 Comments

There is an equation for the diagonal of cuboid…

Diagonal=whole root of sum of squares of sides

Its not the sqrt of 8100 it the sqrt of 8092.25

I used the pythagorean theorem but somehow got the wrong answer

edit: I forgot to square the √ (40²+40²) which is the length of the bottom side's diagonal line 🙂

This is the easiest one.

It was much easy

He has used the direct formula for calculating the diagonal of cuboid

(l^2+b^2+h^2)whole square root.

It is not a difficult question.

It is just using the formula

Can the umbrella fit?

Yes or no?

Hahahaha

Please tell me that this task was without a calculator to at least count 70 square + 2 x 40 square and take the root of 8100.

Did the students really say the exam was too difficult,

especiallythe umbrella question orexceptthe umbrella question?If the umbrella handle has a radius of more than 5 cm it would not fit into the locker. Is this assumption right on my part?

As a simpleton of course I use pythagoras twice, knowing very well that it is not elegant and that I solve a riddle meant for 12 year olds like a 12 year old.

Too easy for this channel.

this video was really a waste of time

To be precise its 89.99 i Guess!!

Yes it will fit because the length of the diagonal of the locker is 90 cm, and the umbrella is 85 cm long. It won't fit if you put it vertically but it should be stored from point P to point M.

Diagonally

If that was a test in my exam I would probably fail it. Not because it is hard, but because I would overthink it and do something crazy…

I'm guessing that 90>85.

How is this hard???!!!

Got it in less than a second

In school we learned a formular for the space diagonal of a cuboid which is square-root of lenght square + width square + height square which is basically the same method as your 2nd method

That's why i found this task to be very easy

Its a spatial pythygoras, 3 edges instead of 2 edges in the formula. Where is the problem?

Ez

Solved it by watching to the thumbnail: simply using pythagoras you don't even need to do it twoce as doing it once already gives you the answer: yes

Solved it with method 2. As for if being too difficult or not, I suppose that depends if students at the level the test was given for have been taught the pythagorean theorem or not. (or distance formula)